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Spring constant of a thread

  1. May 27, 2009 #1
    1. The problem statement, all variables and given/known data

    A 2.60 g spider is dangling at the end of a silk thread. You can make the spider bounce up and down on the thread by tapping lightly on his feet with a pencil. You soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap exactly once every 4.90 s seconds. What is the spring constant of the silk thread.

    2. Relevant equations

    [tex]\omega[/tex]= 2[tex]\pi[/tex]/T
    [tex]\omega[/tex]= [tex]\sqrt{}k/m[/tex]

    3. The attempt at a solution
    so i equated the 2 equations and tried to isolate for k and this is what my equation looked like : m*(2[tex]\pi[/tex]/T)^2 = k ..i tried rearranging twice and my answer and equation are coming out the same ..pls. help
     
  2. jcsd
  3. May 27, 2009 #2

    Doc Al

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    That looks fine to me. Why do you think it's not?
     
  4. May 27, 2009 #3
    when i put the answer into my hwk the answer is appparently wrong..i was also wondering if i was right in assuming the period to be 4.90 seconds??
     
  5. May 27, 2009 #4

    nrqed

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    What value did you get ? Did you convert the mass to kg ? (I assume they want the k in N/m)
     
  6. May 27, 2009 #5
    the value i am getting is 4.85x10^-3 N/m
     
  7. May 27, 2009 #6

    Doc Al

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    Yes, that was correct.
     
  8. May 27, 2009 #7

    Doc Al

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    Double check your arithmetic.
     
  9. May 27, 2009 #8
    thankx i got it :))
     
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