Static Equilibrium: A 1380 N uniform boom of length ℓ is supported by a cable

AI Thread Summary
To find the tension in the cable supporting a 1380 N uniform boom with a 3604 N weight, the sum of forces in both the x and y directions must equal zero. The tension can be determined by analyzing the torques acting on the system, particularly since the boom is pivoted at the bottom and the cable is attached at a distance of 3/4ℓ from the pivot. Although the length of the boom is not specified numerically, it is represented as ℓ, allowing for a general solution. Understanding the balance of forces and torques is crucial for solving the problem. The key to finding the tension lies in setting up the correct equations based on these principles.
sb42
Messages
3
Reaction score
0

Homework Statement



A 1380 N uniform boom of length ℓ is supported by a cable, as shown. The boom is pivoted at the bottom, the cable is attached a distance 3/4ℓ from the pivot, and a 3604N weight hangs from the boom’s top. Find the tension of the cable.

here is a picture of the diagram
24.media.tumblr(dot)com/tumblr_m3f8sxRH7H1qdg2z1o1_400.jpg[/PLAIN]

Homework Equations



I know that the sum of the forces in the x direction is 0 and the sum of the forces in the y direction is also 0. I am having issues understanding this concept and I don't understand how to even start this.

The Attempt at a Solution



Ive tried buy getting the forces in the x and y direction but it seems as though I should be able to find the tension of the cable without finding these first. One thing that is throwing me off is the fact they don't give and actual length to the rod.
Any help would be appreciated!
 
Last edited:
Physics news on Phys.org
What is the actual question? Find the tension in the cable?
 
Yes, sorry forgot to paste that bit.
 
You should be able to find it fairly easily if you sum of the torques in the system. This should give you a solvable system of equations. They give you the length of the rod, it's total length is L.
 
Thank you!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top