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Statics of structure, distributed load
- Thread starter Morshed awad
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The discussion revolves around solving a statics problem involving an L-shaped beam with distributed loads. The user is struggling with understanding how to manage two confounded loads, specifically the interaction between vertical and horizontal distributed loads. Clarification is sought on the nature of the loads, whether they are uniform or varying. Participants emphasize the importance of calculating reaction forces at points A and B before proceeding. The conversation highlights the need for a clear understanding of the load distribution to effectively solve the problem.
- #2
Nidum
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Morshed awad
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Yes i have calculated the reaction forces but the problem tha i don't know how to work with the part wherethe two distributed load are confounded please lead me and i just want to know about the section thank u
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Not sure I understand the diagram. It seems to be an L shaped beam, assumed rigid at the bend. The distributed load is of uniform density q0 on the vertical section, but what about the horizontal section? The text suggests that is also uniform, but the diagram implies it declines linearly(?) from a max of q0 to zero at the tip.
By "confounded" loads, do you mean the combination of distributed and point loads on the same beam section, or is it the mix of vertical and horizontal loads that bothers you?
By "confounded" loads, do you mean the combination of distributed and point loads on the same beam section, or is it the mix of vertical and horizontal loads that bothers you?
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
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