Stress and strain, maximum applied force before permanent deformation/breakage

AI Thread Summary
The discussion focuses on calculating the maximum longitudinal force a bone can withstand before breaking, given a compressive stress of 2.00e8 N/m^2 and a cylindrical bone with a radius of 1.55 cm. The initial attempt incorrectly calculated torque instead of axial load. The correct approach involves using the formula for axial stress, where the force (P) equals the product of the maximum stress and the cross-sectional area (A) of the cylinder, calculated as A = π * r^2. By applying this formula, the maximum force can be accurately determined. The conversation emphasizes the importance of distinguishing between bending stress and axial stress in such calculations.
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Compute the maximum longitudinal force that may be supported by a bone before breaking, given that the compressive stress at which bone breaks is 2.00e8 N/m^2. Treat the bone as a solid cylinder of radius 1.55 cm. The attempt at a solution
I tried using the equation Max Torque = pi/4 * (r^3) * max stress. Plugged in 0.0155 m for "r" and 2.00e8 N/m^2 for max stress, got 585 N*m for torque, then divided again by 0.0155 m to get the Force (377000 N). This answer wasn't accepted into webassign. What am i missing in the problem solving?
 
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You are calculating max torque or moment due to bending stresses, but the problem is asking, perhaps not too clearly, for max axial (longitudinal) load based on allowable axial stress. Instead of using bending stress = M/S, try using axial stress = P/A.
 
Ok. If P is the compressive force, and A is the cross-sectional area that the force is applied to, I would think that A= ∏*r^2 for the surface of the cylinder. Then, multiplying A by the maximum stress 2e8 N*m^2 would yield P?
 
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