1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Stuck again

  1. Aug 22, 2004 #1
    problem: Simplify F(x) = 1 / ( 1+tan^2 x)^.5 - cos x :0<x<pi/2

    ok the only thing i can think of to substitute in was (1+tan^2 x)^.5 = sec^2 x ...

    so i got the problem down to 1 / (sec^2 x)^.5 + cos and then become stucks

    i m thinken i can just say it is 1 / (sec x) + cos... not sure if that will work or not

    thanks in advance for any help
  2. jcsd
  3. Aug 22, 2004 #2
    You're on the right track...here's a hint: 1\secx = cosx
  4. Aug 22, 2004 #3
    ya but then cos x - cos x = 0....

    (i had actually worked it out using that but i didn't think the answer would be zero... esp since the next problem is the same the only differnce is that it is from pi < x < 3 pi / 2)

    i guess i just needed a second untainted opion... thanks
    Last edited: Aug 22, 2004
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook