Surface Integral Homework: Flux Through a Cylinder

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Homework Statement



The problem asks to find the flux through a cylinder of radius R and height h.

Homework Equations



Flux = ∫∫FndS over S

F = (ix + jy)*ln(x2+y2)

The Attempt at a Solution



After finding the unit normal vector (n) to the curved surface of the cylinder, the integral simplified down to:

∫∫((x2+y2)/√(x2+y2))*ln(x2+y2)dS

I'm wondering if it is ok to replace x2+y2 with R2. Then the integral would be:

∫∫Rln(R2)dS

and since R is a constant

Rln(R2)∫∫dS

= 4*pi*hR2ln(R). which is the correct answer
 
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Yeah,that's OK because you're computing \vec{F}\cdot\hat{n} only on the surface of the cylinder!
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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