Suspended mass

  • Thread starter Ry122
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  • #1
565
2
A ruler is suspended from point x. When a mass is put at point y the mass at x is heavier than when it is at point p.
x-------------------p------------------------y
------------------------------------------------
Why is it that when the mass is moved closer to x the mass at x decreases?
 

Answers and Replies

  • #2
1,710
5
do you mean force?
 
  • #3
84
0
I did not understand the question properly.
You mention that the ruler is suspended from the Point X which is the leftmost point then what effect will the mass have when it is put at the suspension point.

Just to put it into perspective.
Note
[tex]\tau =rXF[/tex]
So at X the value of r is nil.
 
Last edited:
  • #4
84
0
Sorry Tau=rXf
 
  • #5
1,710
5
I did not understand the question properly.
You mention that the ruler is suspended from the Point X which is the leftmost point then what effect will the mass have when it is put at the suspension point.

Just to put it into perspective.
Note
[tex]\tau =rXF[/tex]
So at X the value of r is nil.

yes which means the force at y is zero but the force at x is max
 
  • #6
565
2
Thanks for the help but what I really wanted to know was why t=r x f. I can understand that the torque increases when the force is increased but why is it that when r increases the torque increases?
 

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