Tension of a string between 2 blocks of equal mass on a flat surface

AI Thread Summary
The discussion centers on calculating the tension in a string between two blocks of equal mass being pulled by a force of 17 Newtons. Participants emphasize the importance of using free body diagrams and Newton's Second Law to derive the tension. The equations indicate that the tension can be calculated by considering the forces acting on each block. The solution involves recognizing that both blocks will have the same acceleration due to their equal mass. Overall, the problem is deemed straightforward once the proper approach is applied.
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Homework Statement



What is the tension of a string between 2 blocks of equal mass that are moving due to a pull of 17 Newtons?[PLAIN]http://postimage.org/image/pmoibsy4p/ [/PLAIN]

A. 8.5
B. 0
C. 17
D. 25

Homework Equations



F=ma


The Attempt at a Solution



17


 
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Attempt at a solution is not just 17... haha... Show your equations that you used, so we can help you... Did you draw your FBD's for the 2 masses?
 
Very easy once you have done the equations for both the masses...
 
This is a very straight forward problem.

Newton's Second Law!

If you draw a free body diagram of each block you will have:

ƩFBLOCK1=ma

FPULL - T = ma

ƩFBLOCK2=ma

T = ma

----

You are given that the masses are equal to each other and the system will accelerate at the same rate!
 
Yes Bill Nye Tho, for you it is very easy, but the purpose of this forum is to help people understand what they deal with by letting them do the problem themself, we just aid them when they struggle... Try helping not just showing that you know the answer...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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