The equation for any set of lines passing through an ellipse with the same slope

VonWeber
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Homework Statement



I was tutoring a student and could not answer one of his questions. Prove that y = mx +- square root( a^2*m^2 + b^2 ) is the equation for two lines passing through an ellipse

Homework Equations



(x/a)^2 + (y/b)^2 = 1 is the equation of an ellipse

The Attempt at a Solution



I started by suggesting he implicitly differentiate the equation for an ellipse and put it in the point slope equation, but it turned out to give an equation for dy/dx = m, but not the desired equation. I worked on different approaches at home for half an hour, but I'm stumped.
 
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Passing through an ellipse? As in they're tangent to it?
 
This is a bit confusing. You title this "the equation for any set of lines passing through an ellipse with the same slope" but then give an equation for exactly two lines.

Look at y = mx + \sqrt{ a^2*m^2 + b^2 } and y = mx - \sqrt{ a^2*m^2 + b^2 } separately. Where do they cross the ellipse (x/a)^2 + (y/b)^2 = 1? I think, like genneth, that it is quite possible they intend these to be the two lines that are tangent to the ellipse on opposite sides.
 
Yeah, of course I meant tangent. don't be so nitpicky
 
There's the boring and tedious way, which is to show that the lines intercept the ellipse at a single point -- substitute one into the other, show that the ensuing quadratic has a single repeated root. There's probably some other clever geometrical proof.
 
VonWeber said:
Yeah, of course I meant tangent. don't be so nitpicky
Don't be so nitpicky? You leave out a crucial part of the problem, mis-state another part and you consider that nitpicky? And you are a mathematics tutor?
 
So I take for one part: y² = (mx)² + 2mx√(a²m² + b²) + a²m² + b²
substituting for y² in the equations for an ellipse I get:

x²(1/a² + m/b²) + x[2m√(a²m² + b²)/b²] + a²m² = 0

I don't see how to make it clear that this has a repeated root, and I'm unclear on why that means it is a tangent to the ellipse.
 
Well, when does the equation ax^2 + bx + c = 0 have a repeated root? Chuck it into the quadratic formula and see if you can't spot something obvious.
 
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