The Explosion of a Vessel and Velocity of its Pieces

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A vessel at rest explodes into three pieces, with two equal mass fragments moving at 30 m/s perpendicular to each other. The third piece has three times the mass of the others, and momentum conservation must be applied to determine its velocity. Initially, the kinetic energy of the vessel is zero, but the momentum is also zero, meaning the total momentum after the explosion must remain zero. The discussion emphasizes that while potential energy is not relevant, kinetic energy will increase post-explosion. The user ultimately resolves their calculations, indicating a successful understanding of the problem.
Rave Grrl
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I need some help on how to solve this question, I don't really know how to do this at all.

A vessel at rest explodes, breaking into three pieces. Two pieces having equal mass, fly off perpendicular to one another with the same speed of 30 m/s. The third piece has three times the mass of each other piece. What are the magnitude and direction of it's velocity immediately after the explosion?

I was told that the sum of the potential energy has to equal the final kinetic energy, but isn't there no potential energy at the beginning? :confused:
 
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You don't need to know anything about the potential energy. Whatever chemical potential energy there was has been expended (the problem states immediately after the explosion) so all you have to concern yourself with is the initial kinetic energy and momentum of the fragments and, of course, both of those quantities will be conserved.
 
So the sum of the energy and momentum has to equal zero? Since the initial kinetic energy was zero?
 
Rave Grrl said:
So the sum of the energy and momentum has to equal zero? Since the initial kinetic energy was zero?

In the initial situation,the KE of the body was zero.The momentum of the body was zero.

Hopefully u can project the momentum conservation law on the 2/3 axes of coordinates and with use of the KE conservation law,u can find your answers.

Daniel.

EDIT:OOOOOOOOOOOOOOOOOPSSSSSSSSSSSS!The KE cannot be zero in the initial case,since it would be zero at the end,too,therefore it would be no moving around...
I'm an idiot!
 
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The initial kinetic energy is NOT zero! However, the momentum vector is.
 
The Kinetic Energy will increase as you can see... the initial energy is 0. It probably has chemical potential energy but that's not relevant. MOMENTUM IS CONSERVED. Which means that:

<br /> m_1v_1&#039; + m_2v_2&#039; + m_3v_3&#039; = 0<br />
 
When I try to solve for V3 in that equation I keep getting the square root of a negative number...
 
nevermind I figured it out
 

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