The Nature of Light

  • #1

Homework Statement


A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10 e-5 m, calculate the position of the third maximum in degrees


Homework Equations



Sin Theta(m) = (m + 0.5) Lambda/w

The Attempt at a Solution



Sin Theta(3) = (3 + 0.5)(633 x 10 e-9)/2.2 x 10 e-5
=(3.5)(633 x 10 e-9)/2.2 x 10 e-5
=0.1

Theta(3) = sin-1(0.1)
=5.7 degrees

Therefore, the position of the third maximum is at 5.7 degrees


Does this seem right to anybody?
 

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