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## Homework Statement

A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10 e-5 m, calculate the position of the third maximum in degrees

## Homework Equations

Sin Theta(m) = (m + 0.5) Lambda/w

## The Attempt at a Solution

Sin Theta(3) = (3 + 0.5)(633 x 10 e-9)/2.2 x 10 e-5

=(3.5)(633 x 10 e-9)/2.2 x 10 e-5

=0.1

Theta(3) = sin-1(0.1)

=5.7 degrees

Therefore, the position of the third maximum is at 5.7 degrees

Does this seem right to anybody?