The original mass of a gas in a leaky cylinder

SamQP
Messages
8
Reaction score
0

Homework Statement


A leaky cylinder, at 0oC contains gas with a pressure of 18.0 atmospheres.
After being kept at 20oC for 24 hours, the pressure is now 16.3 atmospheres and the masss has fallen by 1.2kg.
What was the gas' original mass?


Homework Equations





The Attempt at a Solution


My only thought on how to tackle this is far to simple and ignores important factors like the temperature.
All I could think of doing was diving 1.2 by 1.7 to get the mass per atmosphere and then multiply that by 18, however I know this will not be right.

Any help appreciated.
 
Physics news on Phys.org
SamQP said:

Homework Statement


A leaky cylinder, at 0oC contains gas with a pressure of 18.0 atmospheres.
After being kept at 20oC for 24 hours, the pressure is now 16.3 atmospheres and the masss has fallen by 1.2kg.
What was the gas' original mass?


Homework Equations





The Attempt at a Solution


My only thought on how to tackle this is far to simple and ignores important factors like the temperature.
All I could think of doing was diving 1.2 by 1.7 to get the mass per atmosphere and then multiply that by 18, however I know this will not be right.

Any help appreciated.
You know the initial pressure and temperature, but you don't know the volume of the cylinder or the initial number of moles. Call the volume V and the number of moles n0. What is the relationship between the volume and the initial number of moles?

You said that 1.2 kg of gas leave the cylinder. Do you happen to know that molar mass of the gas? If so, then you know the number of moles that exited (Δn), and the new number of moles (n0-Δn). You also know that the new temperature is 20 C and the new pressure is 16.3 atm. How are the new temperature, the new pressure, and the new number of moles related in terms of n0 and V?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top