The position of the object is on the place of the question mark.

  • Thread starter Thread starter Boxter
  • Start date Start date
  • Tags Tags
    Convex Mirrors
AI Thread Summary
A convex mirror with a focal length of 10 cm forms an image one-quarter the size of the object, leading to the equations -1/f = 1/u + 1/v and m = v/u. The correct relationship for the image distance v must account for the sign convention, resulting in v being negative for a convex mirror. The user struggles with finding a common denominator in their calculations, specifically in the equation involving u and 0.25u. The discussion emphasizes the importance of correctly applying the mirror formula and manipulating fractions to solve for u. Understanding these concepts will help clarify the solution process for the problem.
Boxter
Messages
8
Reaction score
0

Homework Statement


A convex mirror of focal length 10cm forms an image that is one quarter the size of the object. Find the position of the object and the image.

Homework Equations


-1/f = 1/u + 1/v
m = v/u

The Attempt at a Solution


m = 1/4
f = 10cm
-1/10 = 1/u + 1/0.25u

I think that 1/u + 0.25u is the problem because I can't find the common denominator. The answer to the question is u = 30cm, v = 7.5cm just in case someone thinks I want them to do my homework for me. I just want to understand how to get it. Thanks.
 
Physics news on Phys.org
Please help someone
 
Dude, relax. Getting impatient after just one hour is not going to help you.
By the way, how does telling us that you know the answer prove anything?

Anyway, your last equation looks correct, except that you need to be careful with the sign of v... the mirror is convex, so it's like a negative lens: it will produce an image on the same side as the object. Hence, v = -0.25u.

Correcting that, you just have a problem with your math. Because in principle,
-1/10 = 1/u - 1/0.25u
is a single equation in one unknown (u), so you can easily solve for u.

Hint: multiply through by u.
 
I still don't understand. The point I'm trying to make is that I don't know how to get the common denominator when there's a fraction and a number. I just need someone to tell me how.
 
OK, you can also combine the two fractions by making a common denominator...

Then can you answer me this: what should be on the place of the question mark in
\frac{1}{u} = \frac{?}{0.25 \cdot u}
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top