- #1
loadsy
- 57
- 0
"The Rate Law" in Chemistry
Hey I've just been working on a chemistry lab lately in my chemistry course, and one of the problems on the lab write-up asks to:
Write the rate law for the following reaction, if it were to occur through a single-step mechanism.
2I^-(aq) + S2O8^2-(aq) -> 2SO4^2-(aq) + I2(aq)
Now since it is asking to write it as a single-step mechanism I would assume there is only one step needed.
Now in the lab it has given us this formula:
rate = -(delta[S2O8^-2])/(delta t) = -(1/2)(delta [I^-])/(delta t) = (1/2)(delta[SO4^2-])/(delta t) = (delta[I2])/(delta t)
So could you not just say the only step needed is:
-(delta[S2O8^-2])/(delta t) = (delta[I2])/(delta t)
Then for the second part to the question it asks "By examination of the experimentally determined rate law, explain whether this reaction does in fact proceed through a single-step mechanism. Explain."
Any help on this problem would be great, thanks.
Hey I've just been working on a chemistry lab lately in my chemistry course, and one of the problems on the lab write-up asks to:
Write the rate law for the following reaction, if it were to occur through a single-step mechanism.
2I^-(aq) + S2O8^2-(aq) -> 2SO4^2-(aq) + I2(aq)
Now since it is asking to write it as a single-step mechanism I would assume there is only one step needed.
Now in the lab it has given us this formula:
rate = -(delta[S2O8^-2])/(delta t) = -(1/2)(delta [I^-])/(delta t) = (1/2)(delta[SO4^2-])/(delta t) = (delta[I2])/(delta t)
So could you not just say the only step needed is:
-(delta[S2O8^-2])/(delta t) = (delta[I2])/(delta t)
Then for the second part to the question it asks "By examination of the experimentally determined rate law, explain whether this reaction does in fact proceed through a single-step mechanism. Explain."
Any help on this problem would be great, thanks.