The relation between incompressibility and divergence-free?

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Incompressibility in fluids is directly related to a divergence-free condition, meaning that for fluids, divergence-free implies incompressibility in all cases. For solids, the relationship is more complex; while small deformations can be characterized by a divergence-free vector field, large deformations complicate this due to the requirement that the determinant of the deformation gradient equals one. This indicates that incompressibility in solids may not strictly adhere to the divergence-free condition under large deformations. Therefore, while divergence-free is a clear indicator of incompressibility in fluids, the same cannot be universally applied to solids without considering deformation scale. Understanding these distinctions is crucial for accurate modeling in finite element analysis.
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Hi all,

One thing I am really confused is the relation between incompressiblity and divergence-free. Since I am coding a finite element code that use mixed displacement and pressure formulation. From what I got from your book. Both incompressible solid and fluid can be characterized by divergence-free vector field (displacement for solid and velocity for fluid). But is this only for small deformation in the case of solid? Since for large deformation, the determinant of deformation gradient must be one, which seems not equivalent to divergence-free.

What about for fluid, because it uses Eularian frame, the divergence-free should be equivalent to incompressibility for any case. Is this correct? Thanks in advance for your clarification!


Mengda
 
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phdggg said:
What about for fluid, because it uses Eularian frame, the divergence-free should be equivalent to incompressibility for any case. Is this correct? Thanks in advance for your clarification!

You are correct.
 
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