Theoretical doubt with rolling without slipping

AI Thread Summary
The discussion centers on the calculation of torque in a rolling without slipping problem, specifically questioning why the torque is represented as Fd. It is clarified that while force F has a tangential component that creates torque, other components like the normal force and gravitational force do not contribute since their lines of action pass through the center of the object. The key point is that both methods of calculating torque—using the tangential component or the total force—yield the same result due to the relationship between distance and force application. This insight helps resolve the initial confusion about the geometric aspects of torque calculation. Understanding this equivalence simplifies the approach to solving the problem.
Hernaner28
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Hi. I'm taking a look at this problem:

attachment.php?attachmentid=48748&stc=1&d=1340990540.gif


And my doubt is with step 2 when he calculates the torque. He just says it is Fd. But...why? F only has a component which effectivly does torque.

Thanks
 

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Hi Hernaner28!

Hernaner28 said:
And my doubt is with step 2 when he calculates the torque. He just says it is Fd. But...why? F only has a component which effectivly does torque.

Thanks

F as a whole is the component which creates effective torque. Fn doesn't create torque as its line of action passes through the ball's center, and the same with mg. But F has a line of action that is at a distance 'd' away from the center and perpendicular to it. So... :wink:
 
I don't understand. F has a tangential component and that's the one which creates torque, the other component of F doesn't create torque because it passes through the center. Maybe it's a geometric problem I cannot solve...

Thanks!
 
Hernaner28 said:
I don't understand. F has a tangential component and that's the one which creates torque, the other component of F doesn't create torque because it passes through the center. Maybe it's a geometric problem I cannot solve...

Thanks!

Yes. But both the torques, that is the torque taken with the tangential component, or just taken the way it is, give you the same result! That's because for the tangential component, the perpendicular distance from the center is R, but in the case of the force given, it is d. Think about it...
 
Ahhmmm I see... I didn't know you could take that easy way.. Thanks!
 
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