- #1
Jacob87411
- 171
- 1
I have this reaction:
CH4+4(O2+3.76) --> CO2+2H2O+2O2+15.04N2
Through other calculations and given information I have found that the mass flow rate of the air (the O2+3.76N2) is 25kg/s and the mass flow rate of the fuel is .87 kg/s. I am having the hardest time finding, using these mass flow rates, the number of moles of each product I have. Any help is appreciated
CH4+4(O2+3.76) --> CO2+2H2O+2O2+15.04N2
Through other calculations and given information I have found that the mass flow rate of the air (the O2+3.76N2) is 25kg/s and the mass flow rate of the fuel is .87 kg/s. I am having the hardest time finding, using these mass flow rates, the number of moles of each product I have. Any help is appreciated