Thermodynamics: Brayton Refrigeration Cycle with Regenerator

AI Thread Summary
The discussion revolves around calculating the regenerator effectiveness in a Brayton refrigeration cycle with a regenerator, given specific parameters such as temperatures, mass flow rate, and efficiencies of the turbine and compressor. The user has already determined enthalpy values but seeks to find the enthalpy at points h4 and h6, noting that h4 should ideally equal h1 in an ideal regenerator. The user is uncertain how to calculate h4, suspecting it may relate to turbine efficiency, and requires the isentropic enthalpy h5s for accurate calculations. The effectiveness of the regenerator is proposed to be calculated using the formula Et=(h1-h3)/(h4-h3), indicating that as h4 approaches h1, effectiveness approaches 1. Overall, the discussion highlights the complexities of real versus ideal thermodynamic processes in refrigeration cycles.
Robin Ghoul
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I have a brayton refrigeration cycle with a regeneator same as the picture below only with irreversible regenrator, compressor and turbine (And different values).
p-10e-1a_12666_image010.gif

The given in my problem are:
Ti=0 C, T3= 35 C, T5= -80 C, mass flow rate m= 0.4 kg/s
Turbine efficiency Et=0.85, Compressor efficiency =0.8 and pressure ratio =5
I found h1=273.3 KJ/Kg, h2=552.27 KJ/Kg, h3= 308.5 KJ/Kg, h5=193 KJ/kg
I need to find the regenerator effectiveness
My question are:
1-How to find h4 and h6
2-What is the regenrator efficiency in this case I know if the regenerator was ideal the h4=h1, but I am unable to find the real h4, maybe it has to do with the turbine efficiency but I only have the real h5 I need h5s to find h4...
As fir the regenerator effectiveness I thought it would be Et=(h1-h3)/(h4-h3).. as h4 approaches h1, the effectiveness approaches 1
 
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Also, specific heats are at room temperature
 
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