Thermodynamics: Cp Variation with Temperature Limit

  • Thread starter Thread starter asdf1
  • Start date Start date
  • Tags Tags
    Thermodynamics
AI Thread Summary
The variation of heat capacity at constant pressure (Cp) with temperature approaches a limit of approximately 3R due to the principles of equipartition of energy, which states that energy is distributed equally among all degrees of freedom in a system. This limit is particularly relevant for ideal gases where each degree of freedom contributes 1/2 kT to the energy. As temperature increases, the contributions from additional vibrational modes in solids also align with this limit, as described by Dulong-Petit law. The references provided offer further insights into the specific heat of gases and the behavior of solids under thermal conditions. Understanding these concepts is crucial for grasping the thermodynamic properties of various materials.
asdf1
Messages
734
Reaction score
0
Why does variation of Cp with temperature tends to a limit of ~3R?
 
Physics news on Phys.org
thank you very much!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top