Thermodynamics: Internal Pressure calculus

thesidjway
Messages
2
Reaction score
0
I'm extremely sorry for not using the template. One of my thermodynamics instructors used this relation to prove another result. I know what to do next and the other steps to end up at the final result but I don't know how this result came.
Is it simply mathematics that I'm not aware of, or is this a standard result? In both cases, kindly help me out! I'm stuck

[PLAIN]https://thesidjway.files.wordpress.com/2014/08/kaise.jpg[/IMG

Thanks in Advance
(I'm a first year undergraduate)
 
Last edited by a moderator:
Physics news on Phys.org
thesidjway said:
kaise.jpg
The internal energy U was expressed as U = U (S,V). Have you had anything in your courses on partial differential equations yet? If not, you are going to have big trouble understanding this development as well as all the rest of thermodynamics. Sorry for the bad news.

Chet
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top