Things i forgot how to do/unsure about. Porabola stuff

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The discussion focuses on understanding the properties of parabolas defined by the equation y = A(x - h)^2 + k. Participants confirm that the vertex is located at (h, k) and discuss how the parameters a, h, and k influence the graph's shape and position. Specifically, a affects the width and direction of the parabola, while h and k shift the vertex along the x and y axes, respectively. To find the x-intercepts, users are advised to set y to zero and solve for x, leading to a formula involving the parameters. Overall, the conversation emphasizes clarifying these concepts and solving for x-intercepts in terms of a, h, and k.
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Homework Statement


1) find the vertex, 2) find the x intercepts in terms of a, h, and k, 3) explain how values of a, h, and k affect the graph


Homework Equations


y = A(x - h)^2 + k


The Attempt at a Solution


1) (H,K)
2) aaaahhh i don't know... i just forgot.
3) A determines how wide it is, with a bigger a making a skinnier parabola, a smaller A making a wider parabola, and a negative a making it go upside down. H moves the vertex along the x axis, and K moves it along the Y axis.


is the ones i answered right? also. i would really appreciate a hint as to how to find out 2.

thanks guys
 
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2. In order for you to be on the x-axis, set y=0. So from there, just solve for x. Whenever a problem says solve "x" in terms of a, b, c ... etc., they just want you to have it look like x = a, b, c.

1 & 3 are good.
 
ooo... hm let's check it out.
 
im getting that

A(x-h)^2 = \sqrt{-k}

gives you one and if you subtract -K from this answer, you get the other x axis.
 
x = \frac{\sqrt{-k}}{A} \pm AH


is that right? i am so braindead.
 
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