Three Phase pi-section model of power system transmission lines

AI Thread Summary
The discussion focuses on modeling a three-phase power system transmission line using the "Three-Phase PI Section Line" block in Matlab-Simulink. The user is attempting to calculate the per-phase impedance for distance protection and fault location, but encounters unexpectedly high impedance values. Suggestions from other users highlight a misunderstanding in the implementation, specifically the incorrect addition of capacitance in series with resistance and inductance, and a programming error that leads to geometric progression in impedance calculations. The user acknowledges these mistakes and seeks further clarification on proper modeling techniques. The conversation emphasizes the importance of accurate data handling and understanding of the PI model in power system analysis.
krishkr
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I am using the "Three-Phase PI Section Line" Matlab-Simulink block from Simpowersystems blockset for modelling an electric power system transmission line.

I had obtained the data from a research paper regarding the transmission line specifications (provided as sequence values).

Since I am trying to do actual impedance calculations of each phase for distance protection & fault location purposes, I tried to compute the variation of per phase impedance using a Matlab program (given below).

Code:
 clear all; clc;close all;
    a=exp(deg2rad(120)*1j);  %% a = -0.5000 + 0.8660j
    A = [1 1 1; 1 a^2 a; 1 a a^2]; %% Matrix for Symmetrical component transformation
    Fo = 60;
    
    %% Line Specification using sequence values (taken from paper)
    R10 = [0.0317   0.3192];   L10 = [0.3204   1.0083]./(2*pi*60) ;   C10 = [10.838e-9  7.6493e-9];
    Distance = 1:150; %% in km
    
    for k = 1:length(Distance)
        R10 = R10*Distance(k); L10 = L10*Distance(k); C10 = C10*Distance(k);
        XL10 = (2*pi*Fo)*L10;  XC10 = 1./((2*pi*Fo)*C10);    
        Z10 = R10 + 1j*( XL10 - XC10 );
        
        Z0(k) = Z10(2);     Z1(k) = Z10(1);     Z2(k) = Z1(k);
        Z012 = [Z0(k) 0 0; 0 Z1(k) 0; 0 0 Z2(k)];
        Zabc = A*Z012*((1/3)*(A'));
        
        Zs(k) = Zabc(1); Zm(k) = Zabc(2);
            
    end
    
    figure(1);subplot(2,1,1);plot(Distance,real(Z0));subplot(2,1,2);plot(Distance,imag(Z0));
    figure(2);subplot(2,1,1);plot(Distance,real(Z1));subplot(2,1,2);plot(Distance,imag(Z1));
    figure(3);subplot(2,1,1);plot(Distance,real(Zs));subplot(2,1,2);plot(Distance,imag(Zs));
    figure(4);subplot(2,1,1);plot(Distance,real(Zm));subplot(2,1,2);plot(Distance,imag(Zm));
The program takes the system data of the transmission line (which are given in unit/km), which can be used as parameters for the Simulink 3 phase pi-section block.
The distance is multiplied to the data to get the actual values.
The impedances are computed, the sequence impedances and the per phase impedances are found out. The values of resistance and reactance are computed from the real part and imaginary part respectively. This operation is done for various distances and the plot shows that.

I find that the values plot rise to very high values (order of 1e200). How can current flow if impedance is so high ? If the system data is inappropriate, please tell me why.
Please suggest the reason for such a problem and how can I overcome it?
Thanks in advance :)
 
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Why are you adding the capacitances to Z10? In the PI model, you should also have an admittance part, where you would have G and C (where G is usually neglected)... Check for instance "Power System Analysis and Design" from Glover.

M.
 
Thank you Mbert. It was stupid of me to add the capacitance as if it was in series with the R and L. Also, I did a programming mistake; the above code repetitively multiplies R10, L10, C10 with Distance. I unintentionally end up with a geometric progression.
 
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