What is the optimal time-base setting for a c.r.o display?

  • Thread starter Thread starter Janiceleong26
  • Start date Start date
  • Tags Tags
    Base Time
AI Thread Summary
To determine the optimal time-base setting for a cathode ray oscilloscope (C.R.O) display, one must calculate the period of the signal, which in this case is 0.02 seconds per revolution. The display width of 10 cm suggests that a time base setting should allow for approximately 5 revolutions to be visible. It is essential to select a time base that distinctly shows separate pulses without them appearing too close together. A slower setting may display more pulses, but could result in overlapping, while a faster setting might only capture part of a pulse. The goal is to find a balance that effectively visualizes both positive and negative voltage changes as the signal cycles.
Janiceleong26
Messages
276
Reaction score
4

Homework Statement



image.jpg

How to find the time-base setting?

Homework Equations


None

The Attempt at a Solution


Firstly, I calculated the period of the revolution..
3000 Rev -> 60s
1 Rev -> 0.02s
Then, how to calculate the time base setting?

Do we need to estimate which is the most suitable one?
If the display is 10cm wide then, 0.1/0.02= 5 rev ?
 
Physics news on Phys.org
Yes, estimating the most suitable one is the way to go. Work out how many cycles of the signal will appear on the display for each of the timebase settings and select one that will most distinctly show (to the naked eye) separate pulses.
 
gneill said:
Yes, estimating the most suitable one is the way to go. Work out how many cycles of the signal will appear on the display for each of the timebase settings and select one that will most distinctly show (to the naked eye) separate pulses.
Ok, thanks !
 
This is a tricky question. Obviously the slowest setting will show the most pulses, but will they appear too close together? The fastest setting might show only one pulse or only part of it. Also the pulse should go both positive and negative (volts) as the magnet passes the coil.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top