Time period of a conical pendulum by D'Alembert's principle

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Homework Help Overview

The discussion revolves around finding the time period of a conical pendulum using D'Alembert's principle. The problem is set within the context of classical mechanics, specifically focusing on the dynamics of a pendulum with a fixed string length and no dissipative forces.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply D'Alembert's principle using a cylindrical coordinate system but encounters difficulties due to the lack of a vertical component in the virtual displacement. Some participants suggest considering virtual displacements in the angular direction, while others question the presence of acceleration in that direction, given that the angle theta is assumed constant during motion.

Discussion Status

The discussion is ongoing, with participants exploring different coordinate systems and the implications of virtual displacements. Some guidance has been offered regarding the use of Cartesian coordinates and the need to incorporate constraints, but no consensus has been reached on the approach to take.

Contextual Notes

Participants are navigating the constraints imposed by the fixed length of the string and the assumptions about the motion of the pendulum, particularly regarding the constancy of the angle theta.

justwild
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Homework Statement


Finding the time period of a conical pendulum by D'Alembert's principle. The string is of a constant length and all dissipations are to be ignored.

Homework Equations


The time period of a conical pendulum is 2\pi \sqrt{\frac{r}{g\tan\theta}}. I need to arrive at this result starting from the D'Alembert's principle.

The Attempt at a Solution


I assume a cylindrical coordinates system whose origin coincides with the fulcrum of the pendulum. Thus, for the conical pendulum with constant string length, the acceleration of the particle would be
\ddot{\vec{r}}=\ddot{\rho}\hat{\rho}+\rho\ddot{\phi}\hat{\phi}.
Now the virtual displacement can be given as
\delta\vec{r}=\rho\delta\phi\hat{\phi}.
And the force acting on the particle as \vec{F}=-mg\hat{z}.

Now if I substitute all these in the D'Alembert's principle, I won't be able to calculate the time period from there. This is obvious because the virtual displacement does not contain the \hat{z} term and due to the dot product, the expression won't include any g term which is necessary because the result does contain the g term.
I am out of ideas for now and I would appreciate anyone from the PF helping me out.
 
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Hello, justwild.

What about virtual displacements in the ##\hat{\theta}## direction. For acceleration in spherical coordinates see here.
 
TSny said:
What about virtual displacements in the ##\hat{\theta}## direction.
I don't understand. Even if I assume a spherical coordinates system why would there be a component of acceleration in the ##\hat{\theta}## direction?
Isn't ##\theta## supposed to remain constant during the motion?
 
justwild said:
I don't understand. Even if I assume a spherical coordinates system why would there be a component of acceleration in the ##\hat{\theta}## direction?
Isn't ##\theta## supposed to remain constant during the motion?

Yes, for the particular solution that you are considering θ will remain constant. However, in http://en.wikipedia.org/wiki/D'Alembert's_principle]d'Alembert's[/PLAIN] principle you can consider any virtual displacement that doesn't violate the physical constraint of the system.
 
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Use Cartesian co-ordinates. Take the length of the string=constant to be the constraint eq. Find delta(z).
Substitute values in d'alemberts', put delta (z).
You'll be able to find the time period
 

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