Torque calculation of CV joint

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SUMMARY

The discussion focuses on calculating the torque of a Constant Velocity (CV) joint in three specific scenarios: during take-off, on a slope in reverse, and while driving on a straight asphalt road. Key insights reveal that the distribution of weight affects the normal force and, consequently, the torque transmitted through the CV joints. For take-off, the rear wheels bear more weight, while on a slope in reverse, the front wheels carry more weight. On straight asphalt, the weight distribution is approximately equal between the front and rear wheels.

PREREQUISITES
  • Understanding of torque calculations in automotive engineering
  • Familiarity with Constant Velocity (CV) joints
  • Knowledge of weight distribution effects on vehicle dynamics
  • Basic principles of friction and normal force
NEXT STEPS
  • Research torque calculation methods for CV joints in various driving conditions
  • Study the impact of weight distribution on vehicle performance
  • Learn about friction coefficients and their role in torque transmission
  • Explore advanced automotive dynamics and suspension systems
USEFUL FOR

Automotive engineers, students studying vehicle dynamics, and anyone involved in the design or analysis of front-wheel drive systems will benefit from this discussion.

Gozupa
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TL;DR Summary: help with assignment: find CV joint torque in 3 different situations

Hi, I need help for my assignment. I need to calculate torque of CV joint of truck in 3 cases:
a) CV joint torque on take off
b) CV joint torque on take off on a slope in reverse
c) CV joint torque while driving on straight asphalt road
1714148264329.png

i've found formula (a) in one of my textbooks, but i'm not sure it's correct one. I don't know how to calculate (b) or (c) tbh.
 
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Welcome, @Gozupa !

It is impossible to help you with such limited information.
Are you asked to compare torque values or to calculate them?

CV joints are mainly used in front-wheel drive light vehicles.
Is your truck of that type?

That is important to know in order to properly answer the questions because the maximum possible force of friction between the tires and the asphalt determines the maximum torque that the engine's power can transfer to the wheels via the CV joints.

Once one wheel reaches that limit and starts spinning in place, the transmitted torque on the CV joint is greatly reduced due to lack of resistance from the asphalt.

For each case:
a) On take off: There is more weight (or normal force associated to friction) on the rear wheels than on the front ones.
b) On take off on a slope in reverse: There is more weight (or normal force associated to friction) on the front wheels than on the rear ones.
c) On straight asphalt road: There is about the same weight (or normal force associated to friction) on the rear wheels and on the front ones.
 
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Likes haruspex, berkeman and BvU
Lnewqban said:
c) On straight asphalt road: There is about the same weight (or normal force associated to friction) on the rear wheels and on the front ones.
At constant speed, that is.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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