Torque on a rotating solid conducting cylinder in B field

merrypark3
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Homework Statement


panofsky 10.3

Find the torque on a solid conducting cylinder rotating slowly in a uniform magnetic field perpendicular to the axis of the cylinder.





The Attempt at a Solution



let the radius of cylinder r, and the conductivity is σ, the rotating angular velocity is \stackrel{\rightarrow}{ω}

j=σ(u×B)=ρv=σ((ω×r)×B)
\stackrel{\rightarrow}{j}=σ((\stackrel{\rightarrow}{ω}×\stackrel{\rightarrow}{r}) ×\stackrel{\rightarrow}{B})=ρ\stackrel{\rightarrow}{v}


\stackrel{\rightarrow}{τ}=∫(ρ\stackrel{\rightarrow}{v}×\stackrel{\rightarrow}{B} )dV=0

Homework Statement



Is it right?
 
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merrypark3 said:
j=σ(u×B)=ρv=σ((ω×r)×B)
\stackrel{\rightarrow}{j}=σ((\stackrel{\rightarrow}{ω}×\stackrel{\rightarrow}{r}) ×\stackrel{\rightarrow}{B})=ρ\stackrel{\rightarrow}{v}\stackrel{\rightarrow}{τ}=∫(ρ\stackrel{\rightarrow}{v}×\stackrel{\rightarrow}{B} )dV=0
The net torque will not be zero. Your last integral looks like the net force rather than the net torque. Otherwise your expressions look ok to me if ##\vec{v}## denotes the drift velocity of charge carriers. I don't think using ##\rho \vec{v}## for ##\vec{j}##will help much.
 
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