Understanding Why No Torque is Produced at O

  • Thread starter Thread starter princejan7
  • Start date Start date
  • Tags Tags
    produced Torque
AI Thread Summary
The discussion centers on understanding why a specific force system produces no torque about point O. Participants question whether the forces mg (weight) and N (normal force) generate torque around O. It is clarified that torque is calculated based on the perpendicular distance from the line of action of the force to the point of rotation. If the line of action passes through point O, no torque is produced, regardless of the forces involved. The conversation emphasizes the importance of analyzing the geometry of the force application to determine torque effects.
princejan7
Messages
93
Reaction score
0

Homework Statement


http://postimg.org/image/tdocieaxx/

Why does the force system produce no torque about O
don't mg and N produce a torque about O?

Homework Equations





The Attempt at a Solution


 
Last edited by a moderator:
Physics news on Phys.org
princejan7 said:

Homework Statement


http://postimg.org/image/tdocieaxx/

Why does the force system produce no torque about O
don't mg and N produce a torque about O?

Homework Equations



The Attempt at a Solution


attachment.php?attachmentid=68166&stc=1&d=1396239764.png


How is torque about a point calculated?
 

Attachments

  • Untitled.png
    Untitled.png
    31.4 KB · Views: 474
Last edited by a moderator:

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Why are these forces not included in the solution? (Torque Problem)
Replies
12
Views
1K
A hanging ring carrying current in a uniform magnetic field
Replies
10
Views
371
The ratio between two horizontal speeds in this pendulum arrangement
Replies
1
Views
607
Why are the forces on torque tension and not the weight of the mass?
Replies
7
Views
1K
Torque about an accelerating point
Replies
5
Views
3K
Where on a rigid body is a resultant force applied?
Replies
11
Views
1K
Rotation and torque about an accelerating point
Replies
6
Views
2K
How is net torque zero about hinge of rod in ball rod system
Replies
7
Views
3K
How to Apply Derivatives in Physics Problems?
Replies
9
Views
1K
Equivalent system (force+couple moment) of a loaded beam
Replies
9
Views
2K

Hot Threads

Recent Insights

Back
Top