Torsoin pendulum with meter stick

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    Meter Pendulum
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A meter stick oscillates with a period of 6.0 seconds when hung from a thin wire and twisted. After being sawed to a length of 70.0 cm, it is rebalanced and set into oscillation again. The formula for the period involves the moment of inertia and torsion constant, but the specific values for these parameters were not provided in the problem. The correct period for the shorter stick is determined to be 3.5 seconds, with the solution found in an archived forum thread. This highlights the importance of understanding the moment of inertia in torsional oscillation problems.
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Homework Statement



A meter stick is hung at its center from a thin wire. It is twisted and oscillates with a period of 6.0 s. The meter stick is sawed off to a length of 70.0 cm. This piece is again balanced at its center and set in oscillation.

Homework Equations



T = 2PI / (omega) = 2PI * (sqrt(I/k)) where I = m.o.i and k =torsion constant

The Attempt at a Solution



I managed to get the value for the two period

T = T_0 * sqrt (I / I_0) where T_0 and I_0 are the initial parameters. The problem is the question does not state the I and I_0. I tried considering it to be a thin rod but failed. The correct answer is 3.5s.
 

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