Why Is the Total Angular Momentum of a Particle System Constant?

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The total angular momentum of a particle system is defined as the vector sum of the angular momentum of each particle relative to a chosen origin. In a system where only internal forces act between particles, these forces are equal in magnitude and opposite in direction, satisfying Newton's third law. By applying Newton's second law, the time derivative of the total angular momentum can be expressed as the sum of the torques due to these internal forces. Since internal forces do not change the total angular momentum, it can be shown that the total angular momentum remains constant over time. Thus, the total angular momentum of the system about the origin is conserved.
ElDavidas
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hey everyone, I've been working through a past paper and I'm stuck on a question:

"(a) Consider a system consisting of n distinct particles P1, P2, : : :, Pn, with masses m1, m2, ..., mn and position vectors r1, r2, : : :, rn, relative to the origin O of an inertial frame, respectively.

For each i = 1, 2, : : :, n, suppose that the only forces acting on Pi are internal forces Fij , which always act along the line joining Pi and Pj , for j = 1, 2, : : :, n and j doesn't equal i.

Assume that Fij = ¡Fji for i = 1, 2, : : :, n, j = 1, 2, : : :, n and i doesn't equal j.

Define what is meant by the total angular momentum of the system about O.

Show, as a consequence of Newton's second law, that the total angular momentum of the system about O is constant."

I can define the total angular momentum of the system, it's the 2nd part of the Q I have trouble with. :confused:

Thanks
 
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Use the defintion of angular momentum:

\vec L = \vec r \times \vec p

Take the time derivative and sum over all particles noting that

\frac {d \vec p}{dt} = \vec F

You will find d\vec L /dt = 0.
 
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