Transfer of Heat: mass of liquid helium that boils?

AI Thread Summary
The discussion revolves around calculating the mass of liquid helium that boils away from a spherical container at 4.2 K, surrounded by a shield at 72.8 K, over 19.2 hours. The net power transfer is calculated using the Stefan-Boltzmann Law, considering the container's area as a perfect blackbody radiator. The user initially calculates the net power but encounters an error in determining the mass of helium vaporized using the latent heat of vaporization. Clarifications suggest ensuring the correct area is used in calculations and that separate Q values may need to be considered for accuracy. The key takeaway is the importance of precise calculations in thermodynamic heat transfer scenarios.
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Liquid helium is stored at its boiling-point temperature of 4.2 K in a spherical container (r = 0.251 m). The container is a perfect blackbody radiator. The container is surrounded by a spherical shield whose temperature is 72.8 K. A vacuum exists in the space between the container and shield. The latent heat of vaporization for helium is 2.1 x 104 J/kg. What mass of liquid helium boils away through the venting valve in 19.2 hours?


I have tried calculating the net Powere first withthe equation Pnet =e sigma (5.67*E -8) A(.251*.251*pi) ( T^4-Tenvirnment^4) this gives me
.315210793711 as my Pnet. then I plug it into the formula Q=Pt Q=P*69120 secs) = 21787.3700613. My last step is to plug it into Q=mLv which is my new specific heat divided by my liquid heat of vaoprization of helium which is 2.1*E4 I get 1.03749, which is incorrect. I am not sure where I am going wrong . should I be calculating separate Q values from the beginning with different e values?
 
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For one thing the area of a sphere is 4\pir2.

So one calculates the P (W) from the Stefan-Boltzmann Law - using the correct area.

Then with power * time = Q, and one can then use the latent heat to find the mass.
 
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