Tricky Integration with Trig Substitution

bjohnson2001
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Homework Statement



Evaluate.

\int(4-y)\sqrt{4-y^{2}}dy

I have the solution using CAS software here:

2y\sqrt{4-y^{2}}+8sin^{-1}\frac{y}{2}+\frac{1}{3}(4-y^{2})^{3/2}


but I need to do this by hand. I have researched the usual trig methods but am having some difficulty. Can someone please help me find the right identity?
 
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Substituting y=2*sin(t) looks like a good starting point.
 
I don't think it goes anywhere though, I get:

8cos(t)-4sin(t)cos(t)

when it comes time to bring the original variable back in I get a mess of cos(arcsin(y/2)) but maybe I am missing something
 
bjohnson2001 said:
I don't think it goes anywhere though, I get:

8cos(t)-4sin(t)cos(t)

when it comes time to bring the original variable back in I get a mess of cos(arcsin(y/2)) but maybe I am missing something

If y=2*sin(t) then dy=2*cos(t)dt. I think you are forgetting that. And yes, it does take some work to integrate. If you make a try at it and show your steps I'm sure someone will try to help.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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