I'm searching for the integral that gives arcosu
as we know : ∫u'/[1-u^2]^0.5 dx = arcsinu
derivative of arccosu = -u'/[1-u^2]^0.5 + C
derivative of arcsinu= u'/[1-u^2]^0.5
The Attempt at a Solution
when I type the -u'/[1-u^2]^0.5 on the online integral calculator it always gives me -arcsinu +C
Why it doesn't gives arccosu
is the arccosu=-arcsinu?!
and what is the integral that gives arcosu?