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**Triple Integral ( IS THIS RIGHT??)**

## Homework Statement

Let R be the solid enclosed by the planes x=0, y=0, z=2 and the surface x^2+y^2, where

x[tex]\geq[/tex]0, y[tex]\geq[/tex]0. Compute[tex]\int\int\int[/tex]xdxdydz

## Homework Equations

## The Attempt at a Solution

I did [tex]\int[/tex]0-1[tex]\int[/tex]0-1[tex]\int[/tex](x^2+y^2)-2 xdzdydx

[tex]\int[/tex]0-1[tex]\int[/tex]0-12x-x^3-xy^2 dydx

[tex]\int[/tex]0-1[2xy-x^3y-xy^3/3]0-1 dx

[tex]\int[/tex]0-12x-x^3-x/3dx = 1-1/4-1/6 = 7/12

Can someone tell me if this is the correct answer