Triple integral using cylindrical coordinates

jonnyboy
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Homework Statement


\int\int_{Q}\int(x^4+2x^2y^2+y^4)dV where Q is the cylindrical solid given by \{(x,y,x)| x^2+y^2 \leq a^2, 0\leqz\leq\frac{1}{\pi}\}

Homework Equations



When I convert to cylindrical I get f(r,\theta,z) = r^4\cos^2\theta + 2r^4\cos^2\theta\sin^2\theta + r^2\sin^2\theta, but I just need the bounds for dr, is it? \int^a_0

The Attempt at a Solution


\int^2\pi_0\int^a_0\int^\frac{1}{\pi}_0 f(r,\theta,z)rdzdrd\theta
*the first integral is supposed to be from 0 to 2pi
 
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Your expression for f(r,\theta,z) is incorrect. It might help you to realize that f(x,y,z)=x^4+2x^2y^2+y^4=(x^2+y^2)^2...so f(r,\theta,z)=? :wink:

And yes, r goes from 0 to a.
 
Got it, so f(r,\theta,z) = r^4 Much simpler!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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