Triple Integral: Volume of a Solid

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SUMMARY

The discussion focuses on calculating the volume of a solid using a triple integral, specifically for the region enclosed by the cylinder defined by the equation x² + y² = 9 and the planes y + z = 16 and z = 1. The correct bounds for the integral are established as -3 ≤ y ≤ 3 and 1 ≤ z ≤ 16 - y, with x bounded by -√(9 - y²) ≤ x ≤ √(9 - y²). The final volume calculated is 135π, confirming the setup and execution of the integral.

PREREQUISITES
  • Understanding of triple integrals in multivariable calculus
  • Familiarity with cylindrical coordinates and their applications
  • Knowledge of setting up bounds for integrals in three-dimensional space
  • Proficiency in evaluating integrals involving polynomial functions
NEXT STEPS
  • Study the application of cylindrical coordinates in triple integrals
  • Learn how to visualize and set up bounds for complex regions in 3D
  • Practice evaluating triple integrals with varying limits
  • Explore the relationship between volume and integrals in multivariable calculus
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Students and educators in mathematics, particularly those focusing on calculus and multivariable analysis, as well as professionals involved in mathematical modeling and engineering applications requiring volume calculations.

iamalexalright
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Homework Statement


Been awhile since I've done them and my memory/reasoning isn't so great apparently...

Use the triple integral to find the volume of the given solid:
The solid enclosed by the cylinder
x^{2} + y^{2} = 9
and the planes y + z = 16 and z = 1. 2. The attempt at a solution
Difficulty is always setting up the bounds of the integral...
-3 \leq y \leq 3
1 \leq z \leq 16 - y
having problems with the xwould it be:
-\sqrt{9 - y^{2}} \leq x \leq \sqrt{9 - y^{2}} ?
 
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Sure. The planes don't intersect inside the cylinder. So you can parametrize the integral over the x,y in the circle defining the cylinder without worrying about the z value. If the planes had intersected inside the circle they would have had to give you a more elaborate description of the region.
 
135*pi, cool! Thanks Dick
 
iamalexalright said:
135*pi, cool! Thanks Dick

That's what I get. :)
 

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