Understanding Angular Momentum: A Brief Explanation of Vector Cross Products

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Homework Help Overview

The discussion revolves around the concept of angular momentum and the application of vector cross products, specifically in the context of calculating the cross product of two vectors.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between vector components and their cross products, questioning the mathematical steps involved in the calculation. There is confusion regarding the notation and the interpretation of the cross product results.

Discussion Status

Some participants express confusion about the vector cross product and its properties, while others attempt to clarify the relationships between the unit vectors involved. There is an indication that some understanding is developing, but explicit consensus on the calculations has not been reached.

Contextual Notes

Participants are navigating through the mathematical definitions and properties of vector cross products, with some uncertainty about the notation and the specific calculations presented.

queenspublic
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When doing Angular Momentum, how is it that 2.0(2.12i + 2.12j) x (-3.863i - 1.035j) is equal to 2.0[-2.194k + 8.189k]?
 
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'cos i x j = k and j x i = -k (and ii = jj = 0) :wink:
 
tiny-tim said:
'cos i x j = k and j x i = -k (and ii = jj = 0) :wink:

I don't understand.

cos i x j = k ?

So cos 2.12i x 2.12j = -2.194k ?

Please explain it in numbers. How do I get -2.194k + 8.189k ?
 
queenspublic said:
I don't understand.

cos i x j = k ?

So cos 2.12i x 2.12j = -2.194k ?

he he :smile:

no, I meant because i x j = k :wink:
 
tiny-tim said:
he he :smile:

no, I meant because i x j = k :wink:

O! I get it! Thanks.
 

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