Engineering Understanding Source Transformations in Operational Amplifier Circuits

AI Thread Summary
The discussion centers on confusion regarding source transformations in operational amplifier circuits, particularly in calculating voltage and resistance values. A user struggles with the multiplication of current and resistance, leading to a misunderstanding of the final voltage in a simplified circuit. Clarifications are provided about the feedback resistor (Rf) in the op-amp circuit, which is crucial for understanding the calculations. The user seeks reassurance about potential errors in the provided solution and gains insights from other participants. Overall, the conversation emphasizes the importance of understanding circuit analysis fundamentals.
dwn
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Homework Statement


See Image

Homework Equations



Source Transformations

The Attempt at a Solution



The answer is given, but I do not understand how they got it. When I multiply 9mA and 947.308Ω resistor, I get 8.526...what am I doing wrong? Also, could someone explain how they went on to get the final voltage in the simplified circuit. Don't you just add voltages when they are in series like this...?
 

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8.526 V + 5.4 V = 13.926 V. So what's the problem?
 
According to their calculation they got .947 V
 
What does the Rf represent as well?
 

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9 x 0.947 = 0.947 is obviously wrong, and looks like a typo.
It should be 9 x 0.947 = 8.523.
 
I haven't built up a lot of confidence with circuit analysis, so I wanted to make sure that it was in fact an error on there part. Thanks guys.
 
dwn said:
According to their calculation they got .947 V

For what? We need some context here.

dwn said:
What does the Rf represent as well?

Rf is the resistance in the op-amp feedback path.
 
dwn said:
What does the Rf represent as well?

The feedback resistor. 150k + 0.740k in series.
 
gneill said:
For what? We need some context here.

This is an online homework site and the guided solution provided a step-by-step solution, which is pictured in the first image I attached. AlphaZero already answered my question.

Thank you for the help.
 
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