Understanding the Law of Sines: Explaining Side a Formula

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The Law of Sines states that (sin A/a) = (sin B/b) = (sin C/c), which allows for manipulation based on known values. When given angle C and side c, the formula for side a is derived as a = (c sin A) / sin C. The incorrect expression a = [sin C/(c sin A)] is invalid because it would imply that a has units of "1 over meters," which is not a valid length measurement. Understanding the relationship between angles and lengths, along with basic algebra principles, is crucial for correctly applying the Law of Sines. Proper manipulation of the formula ensures that all sides maintain consistent units.
thakid87
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Not exactly a homework question, even though it is related to my homework...

So, the law is:

(sin A/a) = (sin B/b) = (sin C/c)

So, in certain problems we have to manipulate this law. For example our givens include angle C and side c.

(sin A/a) = (sin C/c)

a would have to equal [(c sin A)/sin C]

Why can't a = [sin C/(c sin A)]

If someone can explain this, I'd greatly appreciate it.

Thanks.
 
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Huh? You just need to transpose 'a' on one side of the equation to get a = (c sin A) / sin C. As for why you can't get that expression is because that's not sin rule.
 
This is nothing more than axioms of Real Numbers and inverse operations, properties of equality. Everyone learns them in Introductory Algebra.
 
thakid87 said:
Not exactly a homework question, even though it is related to my homework...

So, the law is:

(sin A/a) = (sin B/b) = (sin C/c)

So, in certain problems we have to manipulate this law. For example our givens include angle C and side c.

(sin A/a) = (sin C/c)

a would have to equal [(c sin A)/sin C]

Why can't a = [sin C/(c sin A)]
a and c are lengths. They might have units of, say, feet or meters. A and C are angles and while they might have units of degrees or radians. In any case "sin(A)" and "sin(C)" have no units and neither does sin(A)/sin(C). So in the formula a= (sin(A)/sin(C) c, a distance, c, with units, say, of meters, is multiplied by a number with no umits, leaving a to have meters as units as it should.

If you wrote a= [sin(C)/c(sin(A))] instead, you now have c, with its units of meters, in the denominator- that would say that a have units of "1 over meters" which, what ever thaat might mean, cannot be a length.

Certainly you should have learned basic algebra, solving equations, well before starting on trigonometry. If you have
\frac{sin(A)}{a}= \frac{sin(C)}{c}
you might start by multiplying both sides by ac (sometimes called "cross-multiplying"):
c sin(A)= a sin(C)
Now, since you want to solve for a, just divide both sides by sin(C):
c [sin(A)/sin(C)]= a.

If someone can explain this, I'd greatly appreciate it.

Thanks.
 
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