Understanding Thermodynamics: Solving for Resistance and Temperature

  • Thread starter Thread starter ice87
  • Start date Start date
  • Tags Tags
    Thermodynamics
AI Thread Summary
The discussion revolves around solving a thermodynamics problem involving a platinum resistance thermometer, where the resistance R is expressed in relation to temperature Tc through a specific formula. Participants express confusion about how to apply the formula and the significance of the constants R0, A, and B, particularly in the context of given resistance values at known temperatures. There is a consensus that three equations must be set up using the resistance values at the ice point, steam point, and melting point of zinc to solve for the constants. Additionally, the need for more information to determine the temperature of a solution based on the thermometer's length is highlighted. The dialogue emphasizes the challenge of understanding the relationship between resistance and temperature in this context.
ice87
Messages
25
Reaction score
0
another thermodynamics problem

For this one its a combination of the wording and the whole resistance that i don't get.

In the interval between the freezing point of water and 700 degrees C, a platinum resistance thermometer is used for interpolating the temperatures on the international scale the Celsius temperature Tc is given by a formula for resistance R with temperature
R = R0(1 + ATc +BTc^2) where A and B are constants determined by measurements at the ice point, the steam point of water, and the melting point of zinc (419.414 degrees C). (a) If R equals 10.000 ohms at the ice point, 13.946 ohms at the steam point, and 24.174 at the melting point of zinc, find R0, A, and B; (b) When immersed in a solution the length is 25.4 cm. What is the temperature of the solution.

now wtf?
 
Last edited:
Physics news on Phys.org
Resistance is an electrical property of a device.
For metals, resistance increases (almost linearly)
Almost proportional to Temperature in Kelvin.
So expect B to be small.

What is Tc of the ice point? What, then, is Ro?
Do you know what temperature the "steam point" is?
 
ice87 said:
For this one its a combination of the wording and the whole resistance that i don't get.

In the interval between the freezing point of water and 700 degrees C, a platinum resistance thermometer is used for interpolating the temperatures on the international scale the Celsius temperature Tc is given by a formula for resistance R with temperature
R = R0(1 + ATc +BTc^2) where A and B are constants determined by measurements at the ice point, the steam point of water, and the melting point of zinc (419.414 degrees C). (a) If R equals 10.000 ohms at the ice point, 13.946 ohms at the steam point, and 24.174 at the melting point of zinc, find R0, A, and B; (b) When immersed in a solution the length is 25.4 cm. What is the temperature of the solution.

now wtf?
I think you need more information in order to answer b).

AM
 
You see what I don't get is where all the numbers go, and what all the letters in the equation represent. I'm guessing for part A i need to setup 3 equations with 3 variables and R equalling 10.000, 13.946, and 24.174 ohms? and maybe with Tc equalling 0, 100, and 419.414 degrees C respectively?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top