Understanding Velocity in Waves

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SUMMARY

The discussion centers on calculating the mass per unit length (μ) of a guitar string vibrating at a frequency of 110 Hz, with a length of 0.648 m and a tension of 100 N. The correct formula for wave velocity is derived from the tension and mass per unit length, expressed as v = √(T/μ). The confusion arises from the distinction between the speed of sound in air (approximately 343.2 m/s) and the wave velocity on the string, which is calculated to be 142.56 m/s due to the string's physical properties.

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Homework Statement


I was told that a string on a guitar vibrates at a frequency of 110 Hz. The length of the string is .648 m and the tension is 100 N. I was told to find the mass per unit length, μ, of the string. Although I got the correct answer, I was wondering why my initial attempt was incorrect (shown below).

Homework Equations


[itex]f_{n}[/itex] = [itex]\frac{n}{2L}v[/itex]

[itex]v[/itex] = [itex]\sqrt{\frac{T}{μ}}[/itex]

The Attempt at a Solution


dakdX.jpg


(Sorry for the formatting, I don't type in latex really quickly).

In this case, if it's a guitar, why is the velocity of the wave not equivalent to 345 m/s (343.2 m/s)? Why is it so much lower (142.56 m/s)?

Thank you.
 
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Oh, is the velocity referring to the velocity of the vibrating string?

I think I understand now.
 

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