KatieLynn
- 64
- 0
Homework Statement
A 200g object is tied to the end of a cord whirled around on top of a horizontal and frictionless table top in a 2.4 diameter circle at 3 rev/s. Determine a) the velocity of the object b)t he acceleration of the object and c)t he tension in the cord.
Homework Equations
Vc = (2*pi*r)/T
Ac = (Vc^2)/R
Fnet = MA
Ft - Fg =MAc
The Attempt at a Solution
So for A) I got Vc = (2*pi*1.2)(1/3) which equals 22.3 m/s
Then for B) I got Ac=(22.6)^2/(1.2) which equals 425.6 m/s
Now here's where I get lost
I tried doing this but it doesn't come out right...
Fnet = MA
Ft - Fg =MAc
Ft - 196.2 = (20)(425.6)
which means Ft = 8708.2N, I know the answer should be Force of tension = 85.1N, I'm not sure what I'm doing wrong.