Use Poynting's Theorem to show E and B fields are out of phase

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SUMMARY

The discussion focuses on using Poynting's theorem to demonstrate that the electric (E) and magnetic (B) fields in a Fabry-Perot interferometer are 90 degrees out of phase. Participants explored the relationship between E and B fields using the equations E = E0exp((-κ)z+i(kz-ωt)) and B = B0exp((-κ)z+i(kz-ωt+θ). The conclusion reached is that the argument can be effectively made using the law of conservation of electromagnetic energy, rather than solely relying on Poynting's theorem.

PREREQUISITES
  • Understanding of Poynting's theorem and its implications in electromagnetic theory.
  • Familiarity with the Fabry-Perot interferometer and its operational principles.
  • Knowledge of wave equations for electric and magnetic fields in nonconducting media.
  • Basic concepts of electromagnetic energy conservation.
NEXT STEPS
  • Study the derivation and applications of Poynting's theorem in electromagnetic theory.
  • Research the principles of Fabry-Perot interferometers and their significance in optics.
  • Explore the mathematical treatment of wave equations in nonconducting media.
  • Investigate the law of conservation of electromagnetic energy in greater detail.
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism, optical engineering, and anyone interested in the principles of wave behavior in interferometers.

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Homework Statement


In a Fabry-perot interferometer, light is reflected back and forth between 2 highly reflecting parallel mirrors, with a nonconducting medium inside. The waves of magnetic and electric field are 90o out of phase, unlike the case of a wave in free space where they in phase. Develop an argument using Poynting's theorem for why this should be so.


Homework Equations



The Attempt at a Solution


I've thought of using E to calculate H and then say that they're out of phase, but then this method isn't based on Poynting's theorem.
Then I've thought of using the eq.:
E = E0exp((-kapper)z+i(kz-wt))
B = B0exp((-kapper)z+i(kz-wt+theta))
to calculate the Poynting vector, S = 1/mu * (E x B), then somehow show that theta is 90o, but then I don't really know how to do it.
 
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I was under the impression that Poynting's theorem was the law of conservation of electromagnetic energy,
\vec{J}\cdot\vec{E} + \frac{1}{2}\frac{\partial}{\partial t}\left(\epsilon_0 E^2 + \frac{1}{\mu_0}B^2\right) + \frac{1}{\mu_0}\vec{\nabla}\cdot(\vec{E}\times\vec{B}) = 0

Does that give you any ideas?
 
Thanks. I just realized that I was in the wrong direction from the start, I've just now finished the argument using the law of conservation of electromagnetic energy instead.
 

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