Using Gauss's Law on two separated, and infinite plates

Click For Summary

Homework Help Overview

The discussion revolves around the application of Gauss's Law to determine the electric field produced by two infinite, parallel, nonconducting sheets with identical positive surface charge densities. The original poster attempts to analyze the electric field components at various points relative to the sheets, questioning the cancellation of electric fields between the sheets.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the reasoning behind the cancellation of electric fields between the sheets and question the directionality of the electric field vectors. There is a discussion about whether the net electric field should be calculated by subtracting or adding the contributions from each sheet.

Discussion Status

Some participants have offered guidance on the direction of electric fields and the implications of charge polarity. Multiple interpretations of the electric field behavior are being explored, particularly regarding the fields inside and outside the plates.

Contextual Notes

There is a mention of conventional understanding of electric field direction and the implications of having identical surface charge densities on both sheets. The discussion also touches on the need for a Gaussian surface to analyze the electric field effectively.

erick rocha
Messages
2
Reaction score
1

Homework Statement


The figure shows cross-sections through two large, parallel, nonconducting sheets with identical distributions of positive charge with surface charge density σ = 1.06 × 10-22 C/m2. What is the y component of the electric field at points (a) above the sheets, (b) between them, and (c) below them?

Homework Equations



So since they have equal surface density, and their positive polarities are opposite of each other, I would think that they electric fields would just cancell each other out right? Appereantly not. Their elecctric field hace equal magnitude in opposite direction. Why would the doward compnent cancel the upward component?

The Attempt at a Solution


The E field in the in between the plates is zero since the inside component cancel each other out.
On the ouside...
E(net)= E(top)-E(bottom)
=σ/2ε-σ/2ε
=0
But the answer is actually
=σ/ε
 

Attachments

  • Screen Shot 2016-04-03 at 4.05.09 PM.png
    Screen Shot 2016-04-03 at 4.05.09 PM.png
    1.3 KB · Views: 1,077
  • Screen Shot 2016-04-03 at 4.05.09 PM.png
    Screen Shot 2016-04-03 at 4.05.09 PM.png
    1.3 KB · Views: 879
  • Like
Likes   Reactions: BvU
Physics news on Phys.org
Hello erick, :welcome:

I wonder why you write E(net)= E(top)-E(bottom) instead of E(net)= E(top) + E(bottom). Are you aware the ##\vec E## field has a direction ? I think you are: after all, you let them cancel in the space between the plates. So what are the directions above both plates ? And below both plates ?
 
  • Like
Likes   Reactions: erick rocha
BvU said:
Hello erick, :welcome:

I wonder why you write E(net)= E(top)-E(bottom) instead of E(net)= E(top) + E(bottom). Are you aware the ##\vec E## field has a direction ? I think you are: after all, you let them cancel in the space between the plates. So what are the directions above both plates ? And below both plates ?
Thanks for the welcome and the response BuV!
Conventionally we say that the E Field goes from positive to negative and since there is no field inside the object that must mean the E field vector from the top plate with a positively charge surface a must be pointing towards the positive y-axis towards infinity. Also the bottom plate of the bottom surface, that is also positively charged, must be pointing towards the negative y-axis towards infinity. The same logic as why the E field vectors in the middle canceled out.
 
erick rocha said:
Conventionally we say that the E Field goes from positive to negative and since there is no field inside the object that must mean the E field vector from the top plate with a positively charge surface a must be pointing towards the positive y-axis towards infinity
How about reasoning the other way around: E-field points away from positive charge, therefore the two (identical magnitude) contributions cancel in between and add up outside both plates !
 
Review a Gaussian pillbox for a (single) non-conducting sheet and the derivation of the electric
field on either side of the sheet.
Now, as you have surmised, there can be no field between the two parallel sheets.
Now consider the fact that electric field lines originate on positive charges and end
on negative charges (they have to go somewhere).
 

Similar threads

  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
4
Views
3K
Replies
4
Views
1K
Replies
1
Views
1K
Replies
6
Views
1K