Variation of Pressure with Depth

AI Thread Summary
To determine the factor by which total pressure at a depth of 850 m in seawater exceeds surface pressure, the equation P = P(initial) + ρgh is used. The calculated pressure at 850 m is 8.33 x 10^6 Pa, while atmospheric pressure is 1.01 x 10^5 Pa. The total pressure at depth is thus the sum of these two values. To find the factor, the total pressure at depth is divided by the atmospheric pressure. The expected answer should be presented as a ratio, leading to the conclusion that the total pressure is significantly greater at this depth.
jer_hall99
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Homework Statement


By what factor is the total pressure greater at a depth of 850 m of sea water than at the surface where the pressure is one atmosphere? (water density = 1000 kg/m3, one atmosphere pressure = 1.01 x 105 Pascals (N/m2), g = 9.8 m/s2 )


Homework Equations


P=P(initial)+ρgh


The Attempt at a Solution


P=(1.01x10^5)+(1000kg/m^3*9.8m/s^2*850m)
 
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Your calculation gives you the pressure at the depth of 850m. The question is worded...'by what factor is the total pressure greater at a depth of 850m... I think this means you are expected to give your answer as a ratio??
 
ok, well how would I do that? the possible answers to the question are a. 100, b. 83, c. 74, d. 19. That is where I am stuck.
 
using P = hρg I got the pressure due to the water to be 8.33 x 10^6 Pa
Atmospheric pressure is 1.01 x 10^5 Pa
Get the ratio ?
 

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