1. The problem statement, all variables and given/known data We were given six homework assignments for lab. We were required to find the force and angle through three given experiments. 1. Experimental using a force table 2. Graphically using head to tail, etc 3. Analytical using basic means to find the answers 2. Relevant equations I have two problems 1st problem Vector resolution F1 = (.1)gN theta = 30 F2 (.2)gN theta = 90 F3 (.3)gN theta = 225 2nd Problem Vector resolution F = (.3)gN theta = 60 Find fx and Fy Find graphical answer, analytical answer and Experimental answer for each 3. The attempt at a solution 1st Problem attempt at solution Using the force table I got F = (.130)gN Theta = 150 Using Graphical I got F = (.131)gN theta = 162 Now my problem is with analytical I used these equations Rx = Rcostheta Ry = Rsintheta r = sqrt(rx^2 + ry^2) theta = arctan rx/ry rx = .1cos30 + .2cos90 + .3cos225 = -.1255 ry = .1sin30 + .2sin90 + .3sin225 = .038 R = sqrt( -.1255^2 + .038^2) = .131 Theta = arctan .038/-.1255 Theta = 343.2 ???? It seems grossly off. I feel like I am forgetting something, but our book does not even really cover three vectors. I had to look online for how to do it. 2nd problem attempt Using force table Fx = .140gN Fy = .245 gN Using graphical (I plotted this like a 90 degree triangle Fx = .16gN Fy = .25gN Using analytical I know c^2 = a^2 + b^2 so .9 = a^2 + b^2 b / sintheta = R / sin Y sin theta is the angle R casts onto A which equals 60 Sin Y is the angle sides B and A make b / sin60 = .3/sin90 b / .866 = .3 b = .866(.3) = .2598 so Fy = .2598 .9 = .2598^2 + a^2 .9 = .0675 + a^2 .8325 = a^2 = .91 so Fx = .91 ??? Why is it so low as compared to the graphical and experimental? I feel something is off. All of my other calculations were pretty dead on .