Velocity and mass rate of a rocket.

AI Thread Summary
The discussion centers on the rocket equation, which states that the change in velocity (ΔV) of a rocket is determined by the relative velocity of the ejected mass and the initial and final mass ratios. It highlights that while the mass flow rate (dm/dt) plays a significant role in the rocket's operation, it does not affect the final speed if the initial mass, final mass, and ejection velocity remain constant. Increasing the thrust by adding more engines leads to a faster acceleration but does not result in a higher total change in speed due to the compensatory effect of increased mass flow rate. This insight underscores the importance of understanding delta-V in space mission planning. Ultimately, the rocket's performance is governed by its mass ratio and ejection velocity, rather than the size of the engine.
AbigailM
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Homework Statement


A rocket ejects pressurized air with constant relative velocity v_{rel} and moves horizontally. Starting from rest and an initial mass m_{1}, find the speed of the rocket when its mass is m_{2}(m_{2}<m_{1}). How does this result depend on the rate r=dm/dt at which the air is ejected?


Homework Equations


v = v_{0}+v_{rel}ln\frac{m_{1}}{m_{2}}

m(t)=m_{1}+\dot{m}t

The Attempt at a Solution



v=v_{rel}ln\frac{m_{1}}{m_{2}} where v_{0}=0m/s

The result depends on the rate in that the velocity increases as m_2 becomes smaller.

How does this look? Thanks for the help.
 
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Your answer to the first question is correct, but you may want to think some more about the second question. You should try to answer that question under the assumption that m1, m2 and vrel all are fixed values.
 
Ok I think I've got something.

From the continuity equation for mass,
\dot{m}=\rho v A where \rho is the density and A is the area.

\dot{m}=\rho Av_{rel}ln\frac{m_{1}}{m_{2}}

Does this look ok?

Thanks!
 
No, it is simpler than you think.

Your original equation (the rocket equation) is correct, i.e. ΔV = V2 - V1 = Ve ln(m1/m2). Now, the question is if this equation depends on the value of the mass rate, that is, assuming that Ve, m1 and m2 all are constant do ΔV then change if dm/dt change, or in other words, do dm/dt appear in the rocket equation at all?

Looking at the rocket equation the answer is obvious, but the result is perhaps a bit surprising given how present dm/dt is in the derivation leading up to the rocket equation. It means, for instance, that a spacecraft will not end up going faster if you increase the accelerating force by putting on an extra (identical) rocket engine but keep the amount of propellant equal. The increased force will be "compensated" by the increased mass flow rate so that the rocket, while accelerating faster, will use its propellant faster and still end up with the same total change in speed. This means that change in speed for a given engine technology (Ve) and mass ratio (m1/m2) is independent of the "size" of the engine and the reasons why the concept of "delta-Vee" is such a useful concept in space mission design.
 
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