AbigailM
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Homework Statement
A rocket ejects pressurized air with constant relative velocity v_{rel} and moves horizontally. Starting from rest and an initial mass m_{1}, find the speed of the rocket when its mass is m_{2}(m_{2}<m_{1}). How does this result depend on the rate r=dm/dt at which the air is ejected?
Homework Equations
v = v_{0}+v_{rel}ln\frac{m_{1}}{m_{2}}
m(t)=m_{1}+\dot{m}t
The Attempt at a Solution
v=v_{rel}ln\frac{m_{1}}{m_{2}} where v_{0}=0m/s
The result depends on the rate in that the velocity increases as m_2 becomes smaller.
How does this look? Thanks for the help.