Velocity of a boat after feeling the wind force

AI Thread Summary
A 400 kg boat is initially moving at 4.0 m/s at an angle of 30 degrees north of east when it experiences a 100 N wind force at 45 degrees north of east. The acceleration is calculated using F = ma, resulting in 0.25 m/s². The acceleration components are determined, and the final velocity is computed by applying the equations for velocity in both x and y directions over a 10-second interval. The magnitude of the new velocity vector is found using the Pythagorean theorem, and the angle is determined using the inverse tangent function. It's important to consider the signs of the components when calculating the angle.
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Homework Statement


A boat is 400 kg and cruising along with a constant speed of 4.0 m/s in a direction 30 degrees north of east. The boat suddenly begins to feel a force from the wind that is 45 degrees north of east and has a magnitude of 100N. After a 10 second period what is the velocity vector of the boat?


Homework Equations


F = ma
v = vo + at


The Attempt at a Solution


I'm wondering if I'm doing this right.

So I broke velocity into x and y components

vxo = 4cos30
vyo = 4sin30

Found the acceleration : f = ma
100 N = 400 kg * a
a = 1/4 m/s2

Broke acceleration into components
ax = 0.25cos45
ay = 0.25sin45

Plugged into equation vf = vo + at
vx = 4cos30 + 0.25cos45 * 10
vy = 4sin30 + 0.25sin45 * 10

Then I would plug vx and vy into Pythagorean to find the magnitude of the velocity? and use inverse tan (vy/vx) to find the angle?
 
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jahrollins said:

Homework Statement


A boat is 400 kg and cruising along with a constant speed of 4.0 m/s in a direction 30 degrees north of east. The boat suddenly begins to feel a force from the wind that is 45 degrees north of east and has a magnitude of 100N. After a 10 second period what is the velocity vector of the boat?

Homework Equations


F = ma
v = vo + at

The Attempt at a Solution


I'm wondering if I'm doing this right.

So I broke velocity into x and y components

vxo = 4cos30
vyo = 4sin30

Found the acceleration : f = ma
100 N = 400 kg * a
a = 1/4 m/s2

Broke acceleration into components
ax = 0.25cos45
ay = 0.25sin45

Plugged into equation vf = vo + at
vx = 4cos30 + 0.25cos45 * 10
vy = 4sin30 + 0.25sin45 * 10

Then I would plug vx and vy into Pythagorean to find the magnitude of the velocity? and use inverse tan (vy/vx) to find the angle?

Yes. Everything looks good. Make sure you recognize when you need to correct the arctangent, though! (for example, two negative components)
 
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