Velocity of the rocket with changing mass

AI Thread Summary
The discussion focuses on expanding the understanding of rocket velocity with changing mass, particularly after the rocket exits the atmosphere. It highlights the importance of the rocket equation and conservation of momentum, suggesting that the mass change is not limited to atmospheric conditions. The conversation also questions the teacher's assertion that mass changes only until the atmosphere is passed, emphasizing that rockets can still accelerate in a vacuum. Additionally, resources for further exploration of the rocket equation and related calculations are provided. Overall, the thread encourages deeper investigation into rocket dynamics beyond initial atmospheric considerations.
annie.hung
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I want to do something about the rocket. I have done the zero gravity point, escape velocity and the velocity of the rocket with constant mass. But I would like to expand it! PLEASE GIVE ME SOME IDEAS!
It probably is not right, but please read through my notes.
1) http://i53.photobucket.com/albums/g58/hunghoiyanl6/1.jpg"
2) http://i53.photobucket.com/albums/g58/hunghoiyanl6/2.jpg"
3) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3.jpg"
3.1) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3-1.jpg"
3.2) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3-2.jpg"
3.3) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3-3.jpg"

My physics teacher said that the mass (fuel) is changing only upto a point where the rocket passes the atmosphere. Afterwards, it will be a freefall process. If so, what other sort of ideas can I expand on it. Please give me some comments on this 'presentation', and give me some other recommandations on what else I can do.
Thank you very much.
Please contact me via email: annie.hung@tsmail.co.uk

Annie
 
Last edited by a moderator:
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annie.hung said:
I want to do something about the rocket. I have done the zero gravity point, escape velocity and the velocity of the rocket with constant mass. But I would like to expand it! PLEASE GIVE ME SOME IDEAS!
It probably is not right, but please read through my notes.
1) http://i53.photobucket.com/albums/g58/hunghoiyanl6/1.jpg"
2) http://i53.photobucket.com/albums/g58/hunghoiyanl6/2.jpg"
3) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3.jpg"
3.1) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3-1.jpg"
3.2) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3-2.jpg"
3.3) http://i53.photobucket.com/albums/g58/hunghoiyanl6/3-3.jpg"

My physics teacher said that the mass (fuel) is changing only upto a point where the rocket passes the atmosphere. Afterwards, it will be a freefall process. If so, what other sort of ideas can I expand on it. Please give me some comments on this 'presentation', and give me some other recommandations on what else I can do.
Thank you very much.
Please contact me via email: annie.hung@tsmail.co.uk

Annie
There are numerous sources on the internet for the derivation of the rocket equation. Some of them are good, and some are not. One that I think does a very good job of setting up the equation in terms of conservation of momentum is found here

http://ed-thelen.org/rocket-eq.html

I think this approach is far superior to anything that involves F = d(M*V)/dt = V*dM/dt + M*dV/dt. This latter equation is only useful under special circumstances. For example, if fuel were being expelled out of both sides of the rocket perpendicular to its direction of motion dM/dt would be the rate of losing mass, but there would be no change in velocity and no net force.

I'm not sure the point your teacher was making about the mass changing only up to the point where the rocket passes the atmosphere. While in the atmosphere there is an effect related to the pressure of the exhausted gas helping to push the rocket. This effect is ignored in the derivation I posted, and it is not needed for the roicket to have thrust. Ships landed on the moon where there is no atmosphere and lifted off again. A rocket does not need atmosphere to accelerate.
 
Last edited by a moderator:
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Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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