Vertical Force of Each Truck Wheel: 68670N

AI Thread Summary
The discussion centers on calculating the vertical force exerted on the road by each wheel of a truck with a total mass of 28,000 kg, derived from the truck's mass of 12,000 kg and a load of 16,000 kg. The calculation shows that each wheel supports a mass of 7,000 kg, resulting in a vertical force of 68,670 N when multiplied by the acceleration due to gravity. There is a mention of scientific notation errors in the problem statement, emphasizing the need for accurate representation of numbers. Additionally, a new question regarding the thrust exerted by a lorry starting from rest with a specific acceleration is raised, with advice to start a new thread for that topic. The calculations and methods discussed are confirmed to be correct.
fleur
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Homework Statement


A truck (mass 12000 kg) carries a load of 16000kg. What vertical force is exerted on the road by each wheel assuming the mass is uniformly spread?

Homework Equations


F=ma[/B]

The Attempt at a Solution


12000kg+16000kg=28000kg total mass
28000/4=7000kg to get mass on each wheel[/B]
F=ma 7000kgx9.81=68670 N
 
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fleur said:

Homework Statement


A truck (mass 1.2 x 104 kg) carries a load of 1.6 x 104 kg. What vertical force is exerted on the road by each wheel assuming the mass is uniformly spread?

Homework Equations


F=ma[/B]

The Attempt at a Solution


1.2 x 104 kg+1.6 x 104 kg=291.2kg total mass
291.2/4=72.8kg to get mass on each wheel[/B]
F=ma 72.8kgx9.81=714 N
Those numbers in the problem statement are given using scientific notation, although the powers of ten are missing the superscript for the exponents. So for the truck mass, for example, 1.2 x 104 kg should read: 1.2 x 104 kg, which is equivalent to 12000 kg.

Fix your starting numbers accordingly and retry your calculations.
 
gneill said:
Those numbers in the problem statement are given using scientific notation, although the powers of ten are missing the superscript for the exponents. So for the truck mass, for example, 1.2 x 104 kg should read: 1.2 x 104 kg, which is equivalent to 12000 kg.

Fix your starting numbers accordingly and retry your calculations.
I have made the changes is the method i used correct though?
 
I have another question and I have no clue on how to attempt this one

The lorry starts from rest with an acceleration of 2 ms-2.
What is the effective thrust is being exerted?
 
fleur said:
I have made the changes is the method i used correct though?
The method is okay and will deliver the correct result.

If it were me doing the problem I would probably find the total mass then convert that to total weight (multiply mass by g) before finally dividing by four to find the weight (force) supported by each wheel.
 
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fleur said:
I have another question and I have no clue on how to attempt this one

The lorry starts from rest with an acceleration of 2 ms-2.
What is the effective thrust is being exerted?
Please start a new thread for a new question.
 
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