Vertical pressure on soft drink can

  • Thread starter Thread starter reshald
  • Start date Start date
  • Tags Tags
    Pressure Vertical
AI Thread Summary
The discussion focuses on calculating the net inward force on the vertical sides of a soft drink can when internal pressure is reduced to zero. The can's dimensions are provided, and atmospheric pressure is noted as 1 atm or 101325 Nm-2. The initial calculations incorrectly assumed equal pressure on the top and sides, leading to confusion. It is clarified that the net force on the vertical sides ultimately results in zero when considering the direction of forces. The conversation highlights the importance of correctly interpreting the problem and converting measurements accurately.
reshald
Messages
2
Reaction score
0

Homework Statement


In a classroom demonstration, the pressure inside a soft drink can is suddenly reduced to essentially zero. Assuming the can to be a cylinder with a height of 13cm and a diameter of 6.5cm , find the net inward force exerted on the vertical sides of the can due to atmospheric pressure.

Homework Equations


Pressure= force/area
area of a cylinder is 2πrh +2πr2
force due to gravity is mg

The Attempt at a Solution


I know that because there is no pressure inside the can to counteract the air pushing inward, the can collapses but I am not sure how to calculate the force on the vertical sides of the can. Atmospheric pressure is 1 atm at sea level which is 101325 Nm-2. If the pressure on the top of the can is the same as that of the sides than you multiply the pressure by area to get force which gives 6991425 but this is incorrect probably because the pressure on the top isn't the same as the pressure on the sides but I don't know what the formula for it is.
 
Physics news on Phys.org
reshald said:
net inward force exerted on the vertical sides of the can
What's the area of the cylindrical surface of the can?
 
Thank you that fixed it. Also I didn't convert the diameter into meters. Thank you.
 
Actually, this is a very poorly worded question. The net force by the air on the vertical sides of the can has to take into account the direction of the forces, and this results in a net force of zero.

Chet
 
  • Like
Likes billy_joule
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top